Week #7 (Due Sunday, Feb.29)

Different signs indicates change in phase and presence of node consistent with an anti-bonding orbital
Only lowest molecular orbital occupied (E=-1) and n=2
So
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both have same amount of electrons and hence system has no charge
consistent with one pi bond
Radical:


Anion:
a. Bond order on each atom

b. Electron density on each atom

Excess electron density on outer carbons consistent with anionic nature of system
For both the radical and anion the bond orders are the same as the cation as the second molecular orbital has no contribution from the central atom and hence no additional overlap with the end carbons is present.